Optimal. Leaf size=237 \[ \frac{3^{-m-1} e^{3 a-\frac{3 b c}{d}} (c+d x)^m \left (-\frac{b (c+d x)}{d}\right )^{-m} \text{Gamma}\left (m+1,-\frac{3 b (c+d x)}{d}\right )}{8 b}-\frac{3 e^{a-\frac{b c}{d}} (c+d x)^m \left (-\frac{b (c+d x)}{d}\right )^{-m} \text{Gamma}\left (m+1,-\frac{b (c+d x)}{d}\right )}{8 b}-\frac{3 e^{\frac{b c}{d}-a} (c+d x)^m \left (\frac{b (c+d x)}{d}\right )^{-m} \text{Gamma}\left (m+1,\frac{b (c+d x)}{d}\right )}{8 b}+\frac{3^{-m-1} e^{\frac{3 b c}{d}-3 a} (c+d x)^m \left (\frac{b (c+d x)}{d}\right )^{-m} \text{Gamma}\left (m+1,\frac{3 b (c+d x)}{d}\right )}{8 b} \]
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Rubi [A] time = 0.317832, antiderivative size = 237, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 3, integrand size = 16, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.188, Rules used = {3312, 3308, 2181} \[ \frac{3^{-m-1} e^{3 a-\frac{3 b c}{d}} (c+d x)^m \left (-\frac{b (c+d x)}{d}\right )^{-m} \text{Gamma}\left (m+1,-\frac{3 b (c+d x)}{d}\right )}{8 b}-\frac{3 e^{a-\frac{b c}{d}} (c+d x)^m \left (-\frac{b (c+d x)}{d}\right )^{-m} \text{Gamma}\left (m+1,-\frac{b (c+d x)}{d}\right )}{8 b}-\frac{3 e^{\frac{b c}{d}-a} (c+d x)^m \left (\frac{b (c+d x)}{d}\right )^{-m} \text{Gamma}\left (m+1,\frac{b (c+d x)}{d}\right )}{8 b}+\frac{3^{-m-1} e^{\frac{3 b c}{d}-3 a} (c+d x)^m \left (\frac{b (c+d x)}{d}\right )^{-m} \text{Gamma}\left (m+1,\frac{3 b (c+d x)}{d}\right )}{8 b} \]
Antiderivative was successfully verified.
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Rule 3312
Rule 3308
Rule 2181
Rubi steps
\begin{align*} \int (c+d x)^m \sinh ^3(a+b x) \, dx &=i \int \left (\frac{3}{4} i (c+d x)^m \sinh (a+b x)-\frac{1}{4} i (c+d x)^m \sinh (3 a+3 b x)\right ) \, dx\\ &=\frac{1}{4} \int (c+d x)^m \sinh (3 a+3 b x) \, dx-\frac{3}{4} \int (c+d x)^m \sinh (a+b x) \, dx\\ &=\frac{1}{8} \int e^{-i (3 i a+3 i b x)} (c+d x)^m \, dx-\frac{1}{8} \int e^{i (3 i a+3 i b x)} (c+d x)^m \, dx-\frac{3}{8} \int e^{-i (i a+i b x)} (c+d x)^m \, dx+\frac{3}{8} \int e^{i (i a+i b x)} (c+d x)^m \, dx\\ &=\frac{3^{-1-m} e^{3 a-\frac{3 b c}{d}} (c+d x)^m \left (-\frac{b (c+d x)}{d}\right )^{-m} \Gamma \left (1+m,-\frac{3 b (c+d x)}{d}\right )}{8 b}-\frac{3 e^{a-\frac{b c}{d}} (c+d x)^m \left (-\frac{b (c+d x)}{d}\right )^{-m} \Gamma \left (1+m,-\frac{b (c+d x)}{d}\right )}{8 b}-\frac{3 e^{-a+\frac{b c}{d}} (c+d x)^m \left (\frac{b (c+d x)}{d}\right )^{-m} \Gamma \left (1+m,\frac{b (c+d x)}{d}\right )}{8 b}+\frac{3^{-1-m} e^{-3 a+\frac{3 b c}{d}} (c+d x)^m \left (\frac{b (c+d x)}{d}\right )^{-m} \Gamma \left (1+m,\frac{3 b (c+d x)}{d}\right )}{8 b}\\ \end{align*}
Mathematica [A] time = 0.198479, size = 206, normalized size = 0.87 \[ \frac{3^{-m-1} e^{-3 \left (a+\frac{b c}{d}\right )} (c+d x)^m \left (-\frac{b^2 (c+d x)^2}{d^2}\right )^{-m} \left (e^{6 a} \left (b \left (\frac{c}{d}+x\right )\right )^m \text{Gamma}\left (m+1,-\frac{3 b (c+d x)}{d}\right )-3^{m+2} e^{4 a+\frac{2 b c}{d}} \left (b \left (\frac{c}{d}+x\right )\right )^m \text{Gamma}\left (m+1,-\frac{b (c+d x)}{d}\right )+e^{\frac{4 b c}{d}} \left (-\frac{b (c+d x)}{d}\right )^m \left (e^{\frac{2 b c}{d}} \text{Gamma}\left (m+1,\frac{3 b (c+d x)}{d}\right )-e^{2 a} 3^{m+2} \text{Gamma}\left (m+1,\frac{b (c+d x)}{d}\right )\right )\right )}{8 b} \]
Antiderivative was successfully verified.
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Maple [F] time = 0.089, size = 0, normalized size = 0. \begin{align*} \int \left ( dx+c \right ) ^{m} \left ( \sinh \left ( bx+a \right ) \right ) ^{3}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.54627, size = 217, normalized size = 0.92 \begin{align*} \frac{{\left (d x + c\right )}^{m + 1} e^{\left (-3 \, a + \frac{3 \, b c}{d}\right )} E_{-m}\left (\frac{3 \,{\left (d x + c\right )} b}{d}\right )}{8 \, d} - \frac{3 \,{\left (d x + c\right )}^{m + 1} e^{\left (-a + \frac{b c}{d}\right )} E_{-m}\left (\frac{{\left (d x + c\right )} b}{d}\right )}{8 \, d} + \frac{3 \,{\left (d x + c\right )}^{m + 1} e^{\left (a - \frac{b c}{d}\right )} E_{-m}\left (-\frac{{\left (d x + c\right )} b}{d}\right )}{8 \, d} - \frac{{\left (d x + c\right )}^{m + 1} e^{\left (3 \, a - \frac{3 \, b c}{d}\right )} E_{-m}\left (-\frac{3 \,{\left (d x + c\right )} b}{d}\right )}{8 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 2.92055, size = 799, normalized size = 3.37 \begin{align*} \frac{\cosh \left (\frac{d m \log \left (\frac{3 \, b}{d}\right ) - 3 \, b c + 3 \, a d}{d}\right ) \Gamma \left (m + 1, \frac{3 \,{\left (b d x + b c\right )}}{d}\right ) - 9 \, \cosh \left (\frac{d m \log \left (\frac{b}{d}\right ) - b c + a d}{d}\right ) \Gamma \left (m + 1, \frac{b d x + b c}{d}\right ) - 9 \, \cosh \left (\frac{d m \log \left (-\frac{b}{d}\right ) + b c - a d}{d}\right ) \Gamma \left (m + 1, -\frac{b d x + b c}{d}\right ) + \cosh \left (\frac{d m \log \left (-\frac{3 \, b}{d}\right ) + 3 \, b c - 3 \, a d}{d}\right ) \Gamma \left (m + 1, -\frac{3 \,{\left (b d x + b c\right )}}{d}\right ) - \Gamma \left (m + 1, \frac{3 \,{\left (b d x + b c\right )}}{d}\right ) \sinh \left (\frac{d m \log \left (\frac{3 \, b}{d}\right ) - 3 \, b c + 3 \, a d}{d}\right ) + 9 \, \Gamma \left (m + 1, \frac{b d x + b c}{d}\right ) \sinh \left (\frac{d m \log \left (\frac{b}{d}\right ) - b c + a d}{d}\right ) + 9 \, \Gamma \left (m + 1, -\frac{b d x + b c}{d}\right ) \sinh \left (\frac{d m \log \left (-\frac{b}{d}\right ) + b c - a d}{d}\right ) - \Gamma \left (m + 1, -\frac{3 \,{\left (b d x + b c\right )}}{d}\right ) \sinh \left (\frac{d m \log \left (-\frac{3 \, b}{d}\right ) + 3 \, b c - 3 \, a d}{d}\right )}{24 \, b} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \left (c + d x\right )^{m} \sinh ^{3}{\left (a + b x \right )}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (d x + c\right )}^{m} \sinh \left (b x + a\right )^{3}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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